Question

Which of the following represents the factorization of the trinomial below,?x²-14×+48A(x+6)(x-8)B(x-6)(x-8)C(x-4)(x-12)D(x+4)(x-12)

Answer 1

Given the following equation:

$\text{ x}^2\text{ - 14x + 48}$

Let's factorize the given trinomial,

Let's think of factors of 48 that will give you a sum of -14.

Product Factors Sum of Factors

48 1 x 48 49

48 -1 x -48 -49

48 6 x 8 14

48 -6 x -8 -14

Therefore, the factors must be -6 and -8.

We get,

$\text{ x}^2\text{ - 14x + 48 = (x + \_\_)(x + \_\_)}$$\text{ = (x + (-6))(x + (-8))}$$\text{ = (x -6)(x - 8)}$

Therefore, the answer is (x - 6)(x - 8). It is letter B.