Given:
-1/2 is a root of the following equation:
[tex]^2+5+2=0[/tex]First, we will find the value of k
substitute with a = -1/2
so,
[tex]\begin{gathered} k\cdot(-\frac{1}{2})^2+5\cdot(-\frac{1}{2})+2=0 \\ k\cdot\frac{1}{4}-\frac{5}{2}+2=0 \\ k\cdot\frac{1}{4}-\frac{1}{2}=0 \\ k\cdot\frac{1}{4}=\frac{1}{2} \\ k=2 \end{gathered}[/tex]So, the equation will be:
[tex]2^2+5+2=0[/tex]Now, factor the equation:
[tex]\begin{gathered} (2a+1)(a+2)=0 \\ 2a+1=0\rightarrow a=-\frac{1}{2} \\ or,a+2=0\rightarrow a=-2 \end{gathered}[/tex]So, the answer will be:
[tex]a=\mleft\lbrace-2,-\frac{1}{2}\mright\rbrace[/tex]