Points A and B are on opposite sides of a lake. A point C is 105.6 meters from A. The measure of angle BAC is 70.5 , and the measure of angle ACB is 38.83 . Find the distance between points A and B (to the nearest meter).A. 33 mB. 35 mC. 68 mD. 70 m

Respuesta :

From the given information, the sketch of the problem is shown below:

It is required to find the distance between points A and B.

The sum of angles in a triangle is 180ยบ, it follows that:

[tex]\begin{gathered} A+B+C=180^{\circ} \\ \Rightarrow70.5^{\circ}+B+38.83^{\circ}=180^{\circ} \\ \Rightarrow B+109.33^{\circ}=180^{\circ} \\ \Rightarrow B=180^{\circ}-109.33^{\circ} \\ \Rightarrow B=70.67^{\circ} \end{gathered}[/tex]

Recall from the Law of Sines that the following equation holds:

[tex]\frac{AB}{\sin C}=\frac{AC}{\sin B}[/tex]

Substitute the angle measures and side length into the equation:

[tex][/tex]

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