Respuesta :

there is not integer whose square is 26, therefore, 26 is not a perfect square

Explanation

a square number or perfect square is an integer that is the square of an integer

[tex]a=b^2[/tex]

if b is a integer, then a is a perfect square

Step 1

so

let

a= 26

now, replace and solve for b, if b is a integer then a is a perfect square

[tex]\begin{gathered} a=b^2 \\ 26=b^2 \\ square\text{ root in both sides} \\ \sqrt{26}=\sqrt{b^2} \\ \sqrt{26}=b \end{gathered}[/tex]

the square root of 26 is not an integer, so

26 is not a perfect square

so, the answer is

there is not integer whose square is 26, therefore, 26 is not a perfect square

I hope this helps you

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