We have the following system of equations:
[tex]\begin{gathered} -4x+4y=-16\ldots(A) \\ 6x+y=-4\ldots(B) \end{gathered}[/tex]Solving by substitution method.
We will first eliminate y to get the value of x.
If we move 6x in equation B to the right hand side, we get
[tex]y=-4-6x\ldots(C)[/tex]Now, we can substitute this result into equation A. It yields
[tex]-4x+4(-4-6x)=-16[/tex]By clearing parentheses, we get
[tex]-4x-16-24x=-16[/tex]By combining similar terms. we have
[tex]-28x-16=-16[/tex]If we move -16 to the right hand side, we obtain
[tex]\begin{gathered} -28x=-16+16 \\ -28x=0 \end{gathered}[/tex]then, our first result is x=0.
Now, by substituting this result into equation C we get
[tex]\begin{gathered} y=-4-6(0) \\ y=-4 \end{gathered}[/tex]Therefore, the answer is
[tex]\begin{gathered} x=0 \\ y=-4 \end{gathered}[/tex]