Respuesta :

We have the following system of equations:

[tex]\begin{gathered} -4x+4y=-16\ldots(A) \\ 6x+y=-4\ldots(B) \end{gathered}[/tex]

Solving by substitution method.

We will first eliminate y to get the value of x.

If we move 6x in equation B to the right hand side, we get

[tex]y=-4-6x\ldots(C)[/tex]

Now, we can substitute this result into equation A. It yields

[tex]-4x+4(-4-6x)=-16[/tex]

By clearing parentheses, we get

[tex]-4x-16-24x=-16[/tex]

By combining similar terms. we have

[tex]-28x-16=-16[/tex]

If we move -16 to the right hand side, we obtain

[tex]\begin{gathered} -28x=-16+16 \\ -28x=0 \end{gathered}[/tex]

then, our first result is x=0.

Now, by substituting this result into equation C we get

[tex]\begin{gathered} y=-4-6(0) \\ y=-4 \end{gathered}[/tex]

Therefore, the answer is

[tex]\begin{gathered} x=0 \\ y=-4 \end{gathered}[/tex]

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