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m AD : m DB = 1:5
that means mDB= 5 mAD
This is a right triangle so then, using the Pythagorean theorem
(5 mAD)^2 = mAB^2 + mAD^2
mAB = x (the diameter)
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(5 mAD)^2 = x^2 + mAD^2
25 mAD^2 - mAD^2 = x^2
24 mAD^2 = x^2
mAD= √ (x^2/ 24)
mAD= x / (2√6 )
mAD= x √6/ 12
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Answer
mDB= 5 (√6/ 12)* x
[tex]mDB=\frac{5\sqrt[]{6}}{12}x[/tex]_______________________________________________
Do you have any questions regarding the solution?
