Respuesta :

Given:-

[tex]y+2x^2=3-2x[/tex]

To find f(x) and also f(3).

So now to find f(x) we keep y on left hand side and all other terms in right hand side

So we get,

[tex]y=3-2x-2x^2=f(x)[/tex]

So the required solution is,

[tex]f(x)=3-2x-2x^2[/tex]

So now to find the value of f(3). we substitute the value 3 in place of x. so we get,

[tex]\begin{gathered} f(x)=3-2x-2x^2 \\ f(3)=3-2\times3-2(3)^2 \\ f(3)=3-6-18 \\ f(3)=-3-18 \\ f(3)=-21 \end{gathered}[/tex]

So the required solution is -21.

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