A quality inspector examines a sample of 40 strings of lights and finds that 4 are defective. What is the relative frequency of a string of lights being defective? Round your answer to 2 decimal places, if necessary.

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Solution

- The formula for the relative frequency is given below:

[tex]\begin{gathered} rf=\frac{f}{n} \\ where, \\ f=\text{ The number of times the data occurred in an observation} \\ n=\text{ Total frequencies} \end{gathered}[/tex]

- We have been given 4 defective lights and 40 total lights in the sample.

- Thus, we can find the relative frequency of a string of lights being defective:

[tex]\begin{gathered} f=4,n=40 \\ \\ rf=\frac{4}{40}=\frac{1}{10}=0.10\text{ \lparen To 2 decimal places\rparen} \end{gathered}[/tex]

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