Question

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Answer 1

$\begin{gathered} \frac{5x^2+x+7}{x}=\frac{5x^2}{x}+\frac{x}{x}+\frac{7}{x} \\ =(5x+1)+\frac{7}{x} \end{gathered}$

Thus, the required value of p(x) is (5x+1) and k is 7.