Question

A local shop sold 320 cheeseburgers and hamburgers combined the number of cheeseburgers sold was three times the number of hamburgers how many hamburgers were sold

Answer 1

Given: A local shop sold 320 cheeseburgers and hamburgers combined

To Determine: The number of hamburgers sold if the number of cheeseburgers sold was three times the number of hamburgers

Solution

Let x represents the number of cheeseburgers sold and y be the number of hamburgers sold

Therefore

$x+y=320$

Also, the number of cheeseburgers sold was three times the number of hamburgers

$x=3y$

Let us combine the two equations

$\begin{gathered} equation1:x+y=320 \\ equation2:x=3y \\ Substitute,x=3y,into,equation1 \end{gathered}$$\begin{gathered} 3y+y=320 \\ 4y=320 \\ \frac{4y}{4}=\frac{320}{4} \\ y=80 \end{gathered}$

Substitute the y into equation 1

$\begin{gathered} x=3y \\ x=3(80) \\ x=240 \end{gathered}$

Hence, the number of hamburger sold is 80