Question

find x to the nearest 100th if sin x = 7/8

Answer 1

Answer:

x = 61.04°

Explanation:

Given:

$\sin x=\frac{7}{8}$

Take the arcsin of both sides of the equation.

$\begin{gathered} \arcsin(\sin x)=\arcsin(\frac{7}{8}) \\ \implies x=61.04\degree \end{gathered}$

The value of x is 61.04° to the nearest 100th.