First we must obtain the relationship between the grade, the mean and the standard deviation of exam A
[tex]\begin{gathered} z=\frac{x-\operatorname{mean}}{\sigma} \\ z_A=\frac{508-500}{40} \\ z_A=0.2 \\ \end{gathered}[/tex]
Now we have to find the required score for exam B to reach the same ratio factor z
[tex]\begin{gathered} z_B=z_A \\ 0.2=\frac{x_B-350_{}}{20} \\ x_B=0.2(20)+350 \\ x_B=354 \end{gathered}[/tex]
As seen in the calculations, Nevaeh must score 354 on Exam B to equal the score on Exam A