[tex]\begin{gathered} \frac{8}{9}x-\frac{1}{3}x+4=\frac{5}{9}(x+2) \\ \frac{8x-3x}{9}+4=\frac{5}{9}x+\frac{10}{9} \\ \frac{5}{9}x+4=\frac{5}{9}x+\frac{10}{9} \\ \frac{5}{9}x-\frac{5}{9}x=\frac{10}{9}-4 \\ 0=\frac{10}{9}-4 \end{gathered}[/tex]
The answer is None.
