Question

Height = -16x^2 +71x+29 Where X is the number of seconds after the baseball is thrown from the window

Answer 1

The height function with respect to time has been given to be:

$\begin{gathered} H(x)=-16x^2+71x+29 \\ \text{where x represents time(s}econds) \end{gathered}$

a)

At x = 2secs, the height of the ball is:

$\begin{gathered} H(2)=-16(2)^2+71(2)+29 \\ H(2)=-16(4)+142+29 \\ H(2)=-64+142+29 \\ H(2)=107feet \end{gathered}$

Hence, at 2 seconds, the height of the ball is 107 feet

b)

At x = 4secs, the height of the ball is:

$\begin{gathered} H(4)=-16(4)^2+71(4)+29 \\ H(4)=-16(16)+284+29 \\ H(4)=-256+284+29 \\ H(4)=57\text{ f}eet \end{gathered}$

Hence, at 4 seconds, the height of the ball is 57 feet