In the question we are given the slope of the line and passing the point that the line passes through as;
[tex]\begin{gathered} m=-9;(x_1y_1)=(-8,-9) \\ \end{gathered}[/tex]To do this, we would use the formula below;
[tex]m=\frac{y-y_1}{x-x_1}[/tex]We can then substitute the given values into the formula above;
[tex]\begin{gathered} -9=\frac{y-(-9)}{x-(-8)} \\ -9=\frac{y+9}{x+8} \\ -9(x+8)=y+9 \\ -9x-72=y+9 \\ y+9x=-81 \end{gathered}[/tex]Therefore the equation of the line is
Answer:
[tex]y+9x=-81[/tex]