Question

A coin is tossed and a die with numbers 1 - 6 is rolled. What isP(heads and 3)?

Answer 1

Solution

Coin total possible out 2

Die total possible out 6

P(heads and 3)

$\frac{1}{2}\times\frac{1}{6}=\frac{1}{12}$

The final answer

$\frac{1}{12}$