Respuesta :

Let's begin by identifying key information given to us:

[tex]\begin{gathered} 4x^2+48x+128=0 \\ \text{Divide through by ''4'', we have:} \\ \frac{4}{4}x^2+\frac{48}{4}x+\frac{128}{4}=\frac{0}{4} \\ x^2+12x+32=0 \\ x^2+8x+4x+32=0 \\ \text{Factorising we have:} \\ x(x+8)+4(x+8)=0 \\ (x+8)(x+4)=0 \\ \Rightarrow x+8=0,x+4=0 \\ \Rightarrow x=-8,x=-4 \\ \\ \end{gathered}[/tex]

Lesser x = -8

Greater x = -4

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