Question

Data collected on the time it takes in seconds for 83 randomly selected passages of play in a game of rugby were collected. Those times (in seconds) are shown below. - A graph is included to but it only lets me send one picture

Answer 1

mean is the addition of all the times divided by the total number of times

Adding all the rugby times on the first page

$11+1.9+24.4+\ldots+18.5+5=486.4$

Adding all the rugby times on the second page

$14.6+8.6+\cdots+12.9+50.1=703.6$

Adding all the rugby times on the third page

$3.6+46.8+\cdots+9.8+28.4=504$

The total times on the first page is 30

The total times on the second page is 31

The total times on the third page is 22

The mean is

$\begin{gathered} \operatorname{mean}=\frac{486.4+703.6+504}{30+31+22} \\ \operatorname{mean}=\frac{1694}{83} \\ \operatorname{mean}=1694 \end{gathered}$

Hence, the mean is 1694sec