The given equations are:
[tex]\begin{gathered} -10x+8y=-44\ldots\ldots(1) \\ 4x+8y=40\ldots\ldots\text{.}\mathrm{}(2) \end{gathered}[/tex]Subtract equation 1 from 2, we get,
[tex]\begin{gathered} 4x+10x+8y-8y=40+44 \\ 14x=84 \\ x=\frac{84}{14}=6 \end{gathered}[/tex]Now, substitute the value of x in equation 2, we get
[tex]\begin{gathered} 4\times6+8y=40 \\ 8y=40-24=16 \\ y=\frac{16}{8}=2 \end{gathered}[/tex]Thus, the solution is x = 6 and y = 2
