Step1: Write out the given parameters
[tex]\begin{gathered} \text{Diameter}=18\text{feet} \\ \text{Radius}=\frac{diameter}{2}=\frac{18}{2}=9feet \end{gathered}[/tex]We are to find the area of the pool cover and it circumference
Step2: write out the formula
[tex]\begin{gathered} \text{Area of pool cover=}\pi r^2 \\ \text{where }\pi=3.14 \end{gathered}[/tex][tex]\text{Area of pool cover=3.14}\times9^2=254.34square\text{ f}eet[/tex]Hence the area of the pool cover is 254.34 square feet
The circumference of the pool cover is given by
[tex]\begin{gathered} 2\pi r \\ 2\times3.14\times9 \\ 56.52 \end{gathered}[/tex]Therefore the circumference of the pool cover is 56.52 feet
