Question

Mom and Dad have decided to put themselves on a strict budget so that the family can save money to go onvacation. For breakfast, the family decides to spend no more than $20.00 for the week.Each day, the family eats 1/3 of a pound of granola and drinks 2/7 of a liter of milk for breakfast.Milk costs $4,49 per liter, but different types of granola have different prices.If the family only buys one type of granola for the week, what is the price per pound of the most expensivegranola they can afford?Explain your solution using logic, tables, graphs, and/or algebraic reasoning.

Answer 1

For breakfast, the family decides to spend no more than $20.00 for the week.

Each day, the family drinks 2/7 of a liter of milk for breakfast.

For the entire week, the amount of milk consumed is

$7\times\frac{2}{7}=2\; \text{liters}$

Milk costs $4,49 per liter, so the cost of the total amount of milk consumed is

$2\times\ 4.49=\ 8.98$

So, the amount left for the granola is

$\ 20.00-\ 8.98=\ 11.02$

Each day, the family eats 1/3 of a pound of granola for breakfast.

For the entire week, the amount of granola consumed is

$7\times\frac{1}{3}=\frac{7}{3}\; \text{pounds}$

Let x be the price per pound of the most expensive granola they can afford.

$\begin{gathered} \frac{7}{3}\cdot x=\ 11.02 \\ x=\ 11.02\cdot\frac{3}{7} \\ x=\ 4.72 \end{gathered}$

Therefore, the most expensive granola they can afford is $4.72