what is the reading on the scale atT equals 1.0 secondswhat is the reading on the scale at T equals 4 point0 secondswhat is the reading on the scale at T equals 8 point0 seconds

what is the reading on the scale atT equals 10 secondswhat is the reading on the scale at T equals 4 point0 secondswhat is the reading on the scale at T equals class=

Respuesta :

Given Data

we have a person whose mass is m= 79 kg. and rides in the elevator.

velocity vs time graph is given.

first look at the free body diagram of a person

now look all the forces which are acting on a person

person in an elevator that is moving upwards

we can write the equation as

[tex]N-mg=ma[/tex]

Here N is a normal reaction by the bathroom scale, mg is wight force and a acceleration of the elevator

we can write above equation as

[tex]N=mg+ma\ldots\ldots\ldots(1)[/tex]

now we have to calculate acceleration

[tex]a[/tex]

we can see the graph

for the increasing the velocity we can write acceleration as

[tex]a\frac{=v_2-v_1}{t_2-t_1}[/tex]

[tex]\begin{gathered} a=\frac{4-0}{2-1} \\ a=2m/sec^2 \end{gathered}[/tex]

now we can write put the acceleration into equation 1

we have

[tex]\begin{gathered} N=mg+ma \\ N=79\times9.8+79\times2 \\ N=923.2\text{ N} \end{gathered}[/tex]

at t =4 seconds no acceleration then a=0

then we can write

[tex]\begin{gathered} N=mg\text{ } \\ N=79\times9.8 \\ N=774.2\text{ N} \end{gathered}[/tex]

similarly for t=8 seconds

we have

[tex]a=-2m/sec^2[/tex]

from equation (1) we can write as

[tex]\begin{gathered} N=mg-ma \\ N=79\times9.8-79\times2 \\ N=616.2\text{ N} \end{gathered}[/tex]

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