what is the reading on the scale atT equals 1.0 secondswhat is the reading on the scale at T equals 4 point0 secondswhat is the reading on the scale at T equals 8 point0 seconds

Given Data
we have a person whose mass is m= 79 kg. and rides in the elevator.
velocity vs time graph is given.
first look at the free body diagram of a person
now look all the forces which are acting on a person
person in an elevator that is moving upwards
we can write the equation as
[tex]N-mg=ma[/tex]Here N is a normal reaction by the bathroom scale, mg is wight force and a acceleration of the elevator
we can write above equation as
[tex]N=mg+ma\ldots\ldots\ldots(1)[/tex]now we have to calculate acceleration
[tex]a[/tex]we can see the graph
for the increasing the velocity we can write acceleration as
[tex]a\frac{=v_2-v_1}{t_2-t_1}[/tex][tex]\begin{gathered} a=\frac{4-0}{2-1} \\ a=2m/sec^2 \end{gathered}[/tex]now we can write put the acceleration into equation 1
we have
[tex]\begin{gathered} N=mg+ma \\ N=79\times9.8+79\times2 \\ N=923.2\text{ N} \end{gathered}[/tex]at t =4 seconds no acceleration then a=0
then we can write
[tex]\begin{gathered} N=mg\text{ } \\ N=79\times9.8 \\ N=774.2\text{ N} \end{gathered}[/tex]similarly for t=8 seconds
we have
[tex]a=-2m/sec^2[/tex]from equation (1) we can write as
[tex]\begin{gathered} N=mg-ma \\ N=79\times9.8-79\times2 \\ N=616.2\text{ N} \end{gathered}[/tex]