Question

Research shows that 9% of 6th graders in K-6 schools have tried cigarettes and 59% of 7th graders in 8-9 or 7-9 middle schools have tried cigarettes. What is the relative percentage increase, rounded to the nearest percent?

Answer 1

The initial percentage is 9%

Then, the final percentage is 59%.

Then, the relative percentage increase;

$\begin{gathered} C=\frac{x_2-x_1}{x_1}\times100 \\ C=\frac{59-9}{9}\times100 \\ C=\frac{50}{9}\times100 \\ C=5.555\times100 \\ C=556\text{ \%} \end{gathered}$