Given that the half-life of gold-194 is approximately 1.6 days.
We can find how much of a 7-gram sample of gold-194 would remain after 3days using the formula below;
[tex]\begin{gathered} A=A_0(\frac{1}{2})^{\frac{T}{h_{}}} \\ \text{Where A = final amount}=\text{?} \\ A_0=initial\text{ amout}=7\text{ grams} \\ T\text{ =Time}=3\text{days} \\ h=\text{ half life}=1.6\text{days} \end{gathered}[/tex]We would then substitute the parameters into the formula above.
[tex]\begin{gathered} A=7(0.5)^{\frac{3}{1.6}} \\ A=7(0.5)^{1.875} \\ A=1.908 \end{gathered}[/tex]Therefore, the amount of a 7gram sample of gold-194 would remain after 3days is;
Answer: 1.908 gram
