Question

2) p(x) = x² + 3; Find p(1)

Answer 1

$p(1)=4$

Explanation

Step 1

to find p(1) just replace the value of x in the equation

$p(x)=x^2+3$

when x=1

$\begin{gathered} p(x)=x^2+3 \\ p(1)=1^2+3 \\ p(1)=1+3 \\ p(1)=4 \end{gathered}$

I hope this helps you