Given,
The power of i is any integer.
The power of i is even number than the value is -1 or 1.
As know that,
[tex]\begin{gathered} \sqrt[]{-1}=i \\ -1=i^2 \\ i^3=i^2\times i \\ i^3=-1^{}\times\sqrt[]{-1} \\ i^4=i^2\times i^2 \\ i^4=-1\times-1=1 \end{gathered}[/tex]So,
Tamara is incorrect. For integer n, i^n is certain to be 1 or -1 if n is even. if n is odd, i^n could be (sqrt(-1)) pr (-sqrt(-1)).
Hence, option b is correct.