Given data:
* The distance traveled by the air conditioner is,
[tex]d=24\text{ m}[/tex]Solution:
As the air conditioner is falling freely under the action of gravity.
Thus, the acceleration of the air conditioner is equal to the acceleration due to gravity.
[tex]\begin{gathered} a=g \\ a=9.8ms^{-2} \end{gathered}[/tex]As the air conditione ris falling itself from the height.
Thus, the initial velocity of the air conditoner is,
[tex]v_i=0\text{ m/s}[/tex]By the kinematics equation, the final velocity of the air conditioner is,
[tex]v^2_f-v^2_i=2ad[/tex]Substituting the known values,
[tex]\begin{gathered} v^2_f-0=2\times9.8\times24 \\ v^2_f=470.4 \\ v_f=21.69\text{ m/s} \end{gathered}[/tex]Thus, the final velocity of the air conditioner is 21.69 m/s.
By the kinematics equation, the time taken by the air conditioner,
[tex]v_f-v_i=at[/tex]where t is the time taken by the air conditioner to reach the ground,
Substituting the known values,
[tex]\begin{gathered} 21.69-0=9.8t \\ t=\frac{21,69}{9.8} \\ t=2.21\text{ s} \end{gathered}[/tex]Thus, the time taken by the air conditioner ot reach the ground is 2.21 seconds.