Question

Solve the compound inequality.3x+1 <4 or 2x + 5 > 17Graph the solution on the number line.

Answer 1

SOLUTION:

$\begin{gathered} 3x\text{ + 1 }\leq\text{ 4} \\ 3x\text{ }\leq\text{ 4 - 1} \\ 3x\text{ }\leq\text{ 3} \\ \frac{3x}{3}\leq\text{ }\frac{3}{3} \\ x\leq\text{ 1} \end{gathered}$$\begin{gathered} 2x\text{ + 5 }\ge\text{ 17} \\ 2x\text{ }\ge\text{ 17 - 5} \\ 2x\text{ }\ge\text{ 12} \\ \frac{2x}{2}\text{ }\ge\text{ }\frac{12}{2} \\ x\ge\text{ 6} \end{gathered}$