Question

the table and graph shows the distance Javier and chloe are from a motion detector in terms of time Javier table and chloe table photo in the chatwho is moving away from the motion detector faster.

Answer 1

Answer:

Chloe is moving away from the motion detector faster

Explanations:

The one that has the highest rate of change of distance with time is moving away from the motion detector faster.

Let us calculate the rate of change of Javier's distance from the motion detector with time.

$\begin{gathered} \frac{\Delta d}{\Delta t}=\text{ }\frac{10-5}{4-2} \\ \frac{\Delta d}{\Delta t}\text{ = }\frac{5}{2} \\ \frac{\Delta d}{\Delta t}\text{ = 2.5 m/s} \end{gathered}$

Javier is moving with a speed of 2.5 m/s from the motion detector

Then, let us calculate the rate of change of Chloe's distance from the motion detector with time.

$\begin{gathered} \frac{\Delta d}{\Delta t}=\text{ }\frac{12-9}{4-3} \\ \frac{\Delta d}{\Delta t}=\text{ }\frac{3}{1} \\ \frac{\Delta d}{\Delta t}=\text{ 3 m/s} \end{gathered}$

Chloe is moving with a speed of 3.0 m/s from the motion detector

Chloe is moving away from the motion detector faster than Javier