We will have the following:
The information we have:
*Mass of the car: 7 000 kg.
*Mass of water: ?
*Initial velocity of the car: 24.5 m/s.
*Final velocity of the car: 20.0 m/s.
Now, using the conservation of momentum we will have the following:
[tex]7000kg\cdot24.5m/s=20.0m/s(7000kg+m_w)[/tex][tex]\Rightarrow171500kg\cdot m/s=20m/s(7000kg+m_w)\Rightarrow7000kg+m_w=\frac{171500kg\cdot m/s}{20m/s}[/tex][tex]\Rightarrow m_w=8575kg-7000kg\Rightarrow m_w=1575kg[/tex]So, the mass of water collected in the car is 1575 kg.