Given:
The points (3, 1) and (0, -2).
To find: The slope-intercept form of the line
Explanation:
Using the two-point formula,
[tex]\frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}[/tex]Here, we have
[tex]\begin{gathered} x_1=3,y_1=1 \\ x_2=0,y_2=-2 \end{gathered}[/tex]Substituting and solving we get,
[tex]\begin{gathered} \frac{y-1}{-2-1}=\frac{x-3}{0-3} \\ \frac{y-1}{-3}=\frac{x-3}{-3} \\ y-1=x-3 \\ y=x-3+1 \\ y=x-2 \end{gathered}[/tex]Final answer:
The slope-intercept form of the line is,
[tex]y=x-2[/tex]