What is the equation of the graph below?On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum of negative 1 and a maximum of 1. It goes through 1 cycle at 2 pi.y = cosine (x + pi/2 )y = cosine (x + 2 pi) y = cosine (x + pi/3)y = cosine (x + pi)

What is the equation of the graph belowOn a coordinate plane a curve crosses the yaxis at 0 negative 1 It has a minimum of negative 1 and a maximum of 1 It goes class=

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ANSWER:

4th option: y = cosine (x + pi)

STEP-BY-STEP EXPLANATION:

For the function y = cosine (x), when x = 0, y = 1 and when x = , y = -1. The graph shows the opposite, when x = 0, y = -1 and when x = , y = 1, so we must add the same amount x = , for y to be positive 1.

So the equation of the graph would be:

[tex]y=\cos(x+)[/tex]

The correct answer is then the 4th option y = cosine (x + pi)

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