Answer:
[tex]L=5.0\text{ meters}[/tex]
Step-by-step explanation:
Given the formula for the period of the situation, substitute L=4.5 seconds and solve for T.
[tex]\begin{gathered} T=2\pi\sqrt{\frac{L}{9.8}} \\ 4.5=2\pi\sqrt{\frac{L}{9.8}} \\ \frac{81}{4}=2\pi *\frac{L}{9.8} \\ L=\frac{81*9.8}{4*4\pi^2} \\ L=5.0\text{ meters} \end{gathered}[/tex]
