find the lenghth of hypotonuse if one lengh is 6 , leave it simplified redical form

We are given a right triangle and we are asked to determine the length of the hypotenuse. To do that we will use the Pythagorean theorem:
[tex]h^2=a^2+b^2[/tex]Where "h" is the hypothenuse and a and b the other two sides. In this case, the two sides are equal since the triangle is 45 - 45 - 90. We have the following values:
[tex]\begin{gathered} a=6 \\ b=6 \end{gathered}[/tex]Substituting:
[tex]h^2=(6)^2+(6)^2[/tex]Solving the operations:
[tex]\begin{gathered} h^2=36+36 \\ h^2=2(36) \end{gathered}[/tex]Taking square root to both sides:
[tex]h=\sqrt[]{2(36)}[/tex]Now we will use the following property:
[tex]\sqrt[]{ab}=\sqrt[]{a}\times\sqrt[]{b}[/tex]Applying the property:
[tex]h=\sqrt[]{2}\times\sqrt[]{36}[/tex]Solving the operations:
[tex]h=6\sqrt[]{2}[/tex]And thus we have found the hypothenuse in its most simplified form.