12a)
Since there are 2/3 of multigrain bagels of 12 bagels, we can apply the rule of three:
[tex]\begin{gathered} 12\text{ bagels ----- }\frac{3}{3} \\ x\text{ ---------- }\frac{2}{3} \end{gathered}[/tex]
where x denote the multigrain bagels. Then, x is given by
[tex]\begin{gathered} x=\frac{\frac{2}{3}\times12}{\frac{3}{3}} \\ \sin ce\text{ 3/3 is one, } \\ x=\frac{2}{3}\times12 \end{gathered}[/tex]
Then, we have
[tex]\begin{gathered} x=\frac{2\times12}{3} \\ x=2\times4 \\ x=8 \end{gathered}[/tex]
and the answer is 8 multigrain bagels.
12b)
Similarly, we can apply the rule of three as
[tex]\begin{gathered} 10\text{ muffins ----- }\frac{5}{5} \\ y\text{ ---------- }\frac{3}{5} \end{gathered}[/tex]
where y denotes the bran muffins. Then y is given by
[tex]\begin{gathered} y=\frac{\frac{3}{5}\times10}{\frac{5}{5}} \\ \sin ce\text{ 5/5 is one, then} \\ y=\frac{3}{5}\times10 \end{gathered}[/tex]
So, we have
[tex]\begin{gathered} y=\frac{3\times10}{5} \\ y=3\times2 \\ y=6 \end{gathered}[/tex]
and the answer is 6 bran muffins.