3 3 2. Andrea bought 12 bagels and 10 muffins at the bakery. Of these items, of the bagels were multigrain, and of the muffins were bran muffins. 12a. How many multigrain bagels did Andrea buy? multigrain bagels 12b. How many bran muffins did Andrea buy? bran muffins

3 3 2 Andrea bought 12 bagels and 10 muffins at the bakery Of these items of the bagels were multigrain and of the muffins were bran muffins 12a How many multig class=

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12a)

Since there are 2/3 of multigrain bagels of 12 bagels, we can apply the rule of three:

[tex]\begin{gathered} 12\text{ bagels ----- }\frac{3}{3} \\ x\text{ ---------- }\frac{2}{3} \end{gathered}[/tex]

where x denote the multigrain bagels. Then, x is given by

[tex]\begin{gathered} x=\frac{\frac{2}{3}\times12}{\frac{3}{3}} \\ \sin ce\text{ 3/3 is one, } \\ x=\frac{2}{3}\times12 \end{gathered}[/tex]

Then, we have

[tex]\begin{gathered} x=\frac{2\times12}{3} \\ x=2\times4 \\ x=8 \end{gathered}[/tex]

and the answer is 8 multigrain bagels.

12b)

Similarly, we can apply the rule of three as

[tex]\begin{gathered} 10\text{ muffins ----- }\frac{5}{5} \\ y\text{ ---------- }\frac{3}{5} \end{gathered}[/tex]

where y denotes the bran muffins. Then y is given by

[tex]\begin{gathered} y=\frac{\frac{3}{5}\times10}{\frac{5}{5}} \\ \sin ce\text{ 5/5 is one, then} \\ y=\frac{3}{5}\times10 \end{gathered}[/tex]

So, we have

[tex]\begin{gathered} y=\frac{3\times10}{5} \\ y=3\times2 \\ y=6 \end{gathered}[/tex]

and the answer is 6 bran muffins.

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