[tex]\begin{gathered} model=\lparen13\text{ }\frac{1}{2}ft)\lparen\frac{1}{9}) \\ but \\ 13\frac{1}{2}=\frac{\lparen13\ast2)+1}{2}=\frac{26+1}{2}=\frac{27}{2} \\ Hence \\ model=\lparen\frac{27}{\text{2}}ft)\lparen\frac{1}{9})=\frac{27\ast1}{2\ast9}ft=\frac{27}{18}ft=\frac{3}{2}ft \\ The\text{ model will be }\frac{3}{2}ft\text{ tall} \\ \\ Question\text{ 7}) \\ circumference=302ft \\ distance=\text{8}\frac{3}{8}ft=\frac{\left(8\ast8\right)+3}{8}ft=\frac{64+3}{8}ft=\frac{67}{8}ft \\ Columns=\frac{circumference}{distance}=302ft\text{ }\div\frac{67}{8}ft=\frac{\lparen302ft\ast8)}{67ft}=\frac{2416ft}{67ft}=36 \\ There\text{ are 36 columns} \end{gathered}[/tex]
