Suppose the sun casts a shadow off a 20-footbuilding. If the angle of elevation to the sun is 65°,how long is the shadow to the nearest tenth of afoot?20 feet6509.3 feet13.2 feet17.2 feet21.1 feet

Suppose the sun casts a shadow off a 20footbuilding If the angle of elevation to the sun is 65how long is the shadow to the nearest tenth of afoot20 feet65093 f class=
Suppose the sun casts a shadow off a 20footbuilding If the angle of elevation to the sun is 65how long is the shadow to the nearest tenth of afoot20 feet65093 f class=

Respuesta :

The triangle formed by the system in the question is shown below:

The length of the shadow is represented by x.

We can use the Tangent Trigonometric ratio to solve for x.

The ratio is given as

[tex]\tan \theta=\frac{\text{opp}}{\text{adj}}[/tex]

From the diagram above, we have the following parameters:

[tex]\begin{gathered} \theta=65 \\ \text{opp }=20 \\ \text{adj }=x \end{gathered}[/tex]

Hence, we can substitute as

[tex]\tan 65=\frac{20}{x}[/tex]

Solving for x, we have

[tex]\begin{gathered} 2.145=\frac{20}{x} \\ \therefore \\ x=\frac{20}{2.145} \\ x=9.3\text{ feet} \end{gathered}[/tex]

The correct answer is the FIRST OPTION (9.3 feet).

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