Okay, here we have this:
We need to solve the following equation:
[tex]0=x^2-10x+12[/tex]We are going to solve using the general formula for equations of the second degree:
[tex]\begin{gathered} x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4\cdot1\cdot12}}{2\cdot1} \\ =\frac{10\pm\sqrt[]{100-48}}{2} \\ =\frac{10\pm\sqrt[]{52}}{2} \\ =\frac{10\pm2\sqrt[]{13}}{2} \\ =5\pm\sqrt[]{13} \end{gathered}[/tex]Finally we obtain that the answers are:
x₁=5+√13
x₂=5-√13
