We are given that v = 3i + 4j
[tex]\begin{gathered} We\text{ }also\text{ }know\text{ }that\text{ }thedirection\text{ }of\text{ }a\text{ }vector\text{ is given by} \\ tan\theta\text{ = }\frac{v1}{v2} \\ Since\text{ both v1 and v2 are positive, we can conclude that the vector lies in the first quadrant.} \end{gathered}[/tex]
Correct option: graph number three
