ANSWER
d.
EXPLANATION
Let's draw the circuit first,
So, first, we have to solve the parallel,
[tex]R_{parallel}=\frac{1}{\frac{1}{R}+\frac{1}{R}+\frac{1}{R}}=\frac{1}{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}=\frac{1}{\frac{3}{3}}=1\Omega[/tex]The equivalent resistance is,
[tex]R_{eq}=R_{parallel}+R=1\Omega+3\Omega=4\Omega[/tex]Hence, the total resistance in the circuit is 4 Ohms.