Question

what is the average rate of change for the function f(x)=x^3-6x^2+4x+7 over the interval 0

Answer 1

Answer:

-1

Explanation:

Given the function:

$f\mleft(x\mright)=x^3-6x^2+4x+7$

The average rate of change over the interval 0≤x≤5:

$\begin{gathered} \text{Rat of change=}\frac{f(5)-f(0)}{5-0} \\ =\frac{(5^3-6(5)^2+4(5)+7)-(0^3-6(0)^2+4(0)+7)}{5} \\ =\frac{(125-150+20+7)-(7)}{5} \\ =\frac{2-7}{5} \\ =-\frac{5}{5} \\ =-1 \end{gathered}$

The average rate of change for the function over the given interval is -1.