Question

Two factory plants are making TV panels. Yesterday, Plant A produced 2000 panels. Three percent of the panels from Plant A and 10% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 8%?

Answer 1

Let x be the number of panels produced in Plant B, with the given information we can set the following equation:

$2000\cdot0.03+x\cdot0.10=(2000+x)\cdot0.08.$

Simplifying the above equation, we get:

$60+0.10x=160+0.08x\text{.}$

Solving the above equation for x, we get:

$\begin{gathered} 0.10x-0.08x=160-60, \\ 0.02x=100, \\ x=5000. \end{gathered}$

Answer:

$5000.$