Question

The motion in one dimension of a vehicle is recorded on a horizontal axis Ox . It starts from rest at x = -20 m and moves in the positive direction with an acceleration a = 5 m / s² to a final position x , during a time interval t = 10s . What is its final position ( x , = ? ) ?

Answer 1

Given:

The initial distance is

$x_0=-20\text{ m}$

The initial velocity is

$v_0=\text{ 0m /s}$

The acceleration is a = 5 m/s^2.

The time interval is t = 10 s.

To find the final position, x.

Explanation:

The final position can be calculated as

$\begin{gathered} x=x_0+v_0t+\frac{1}{2}at^2 \\ =-20+0\times10+\frac{1}{2}\times5\times(10^)^2 \\ =230\text{ m} \end{gathered}$

Thus, the final position is 230 m