Answer:
• Reaction:
[tex]\begin{gathered} 2C\text{ + 3H}_2\text{ + }\frac{1}{2}O_2\text{ }\rightarrow\text{ CH}_3CH_2OH \\ \Delta H=\text{ Enthalpy change of formation} \end{gathered}[/tex]• Reaction:
[tex]\begin{gathered} (NH_4)_2SO_4\text{ }\rightarrow\text{ 2NH}_4^+\text{ + SO}_4^{2-} \\ \Delta H=\text{ Enthalpy change of solution} \end{gathered}[/tex]• Reaction:
[tex]\begin{gathered} Na_{(g)}^+\text{ }\rightarrow\text{ Na}_{(aq)}^+ \\ \Delta H=\text{ Enthalpy change of hydration} \end{gathered}[/tex]• Reaction:
[tex]\begin{gathered} C\text{ + O}_2\text{ }\rightarrow\text{ CO}_2 \\ \Delta H=\text{ Enthalpy change of combustion} \end{gathered}[/tex]• Reaction:
[tex]\begin{gathered} Na_{(s)}\text{ }\rightarrow\text{ Na}_{(g)} \\ \Delta H=\text{ Enthalpy change of atomisation} \end{gathered}[/tex]• Reaction:
[tex]\begin{gathered} Na_{(g)}\text{ }\rightarrow\text{ Na}^+_{(g)}\text{ + e}^- \\ \Delta H=\text{ Enthalpy change of ionisation} \end{gathered}[/tex]• Reaction:
[tex]\begin{gathered} F_{(g)}\text{ + e}^-\text{ }\rightarrow F_{(g)}^- \\ \Delta H=\text{ Enthalpy change for electron affinity} \end{gathered}[/tex]Explanation:
• Enthalpy change of ,combustion,: is the enthalpy involved in the process of in which a compound burns in the presence of oxygen (or air).
,• Enthalpy change of ,formation,: this enthalpy change is the one involved when 2 or more reactants combine to form a product.
,• Enthalpy change of ,solution,: is the energy present in the dissolution of a substance in a solvent.
,• Enthalpy change of ,hydration,: it is the energy that intervenes when a substance in gaseous atate becomes part of the aqueous solution.
,• Enthalpy change of ,atomisation,: this is necessary to form gaseous atoms from the element under standard conditions.
,• Enthalpy change of ,ionisation,: is the energy involved when an ion is formed.
,• Enthalpy change for ,electron affinity,: is the energy released when a neutral gaseous atom takes on an electron and forms a negative ion.
