Question

A 435 mL solution was made by mixing 201 mL of cyclohexane, Which has a density of 0.78 g/mL, and 257 mL of toluene, Which has a density of 0.87 g/mL. Calculate the volume percentage of the cyclohexane in the solution. Be sure and answer has right number of significant digits.

Answer 1

Answer:

$46.2\text{ \%}$

Explanation:

Here, we want to calculate the volume percentage of cyclohexane in the solution

Mathematically, we have this as:

$\frac{volume\text{ of cyclohexane}}{\text{volume of solution}}\times\text{ 100\%}$

Thus, we have the volume percentage as follows:

$\frac{201}{435}\times\text{ 100 \% = 46.2 \% }$