We have been given a table that indicates Textbook sales (millions of dollars) from the year 2000 to 2005.
Method: Since we have been told to model the equation that best fits the data.
To do this, we have been told to let t represent the years.
We can also represent the textbook sales as Pt
Using a graphing calculator
Question A
Thus, the quadratic model that best fits this data is:
[tex]P_t=-2.68t^2_{1^{^{^{}}\text{ }}}+301.99t_1+4270.07[/tex]
Question B
We are told to predict the Textbook sales in 2015
In 2015, the value of t1 will be
[tex]\begin{gathered} t_1=2015-2000=15 \\ t_1=15 \end{gathered}[/tex]
We can now proceed to substitute
[tex]t_1=15[/tex]
Into the equation
[tex]\begin{gathered} P_t=-2.68\times15^2+301.99\times15+4270.07 \\ P_t=8196.92 \end{gathered}[/tex]
in 2015, we would expect
[tex]P_t\approx8197\text{ million dollars}[/tex]
Thus, approximately 8197 million dollars is expected to be spent on college textbook
Question C
To predict when the total sales will be approximately $7billion,
We will take our value for
[tex]P_t=7000[/tex]
This means that
[tex]7000=-2.68t^2_{1^{^{^{}}\text{ }}}+301.99t_1+4270.07[/tex]
Thus, we will have to find the value of t1
Again, using the graph to predict when Pt = $7000
We can see from the graph that this value is about 9.952 years
So we will try when
[tex]\begin{gathered} t_1=9\text{years} \\ \text{and when} \\ t_1=10\text{years} \end{gathered}[/tex]
Using the model
[tex]P_t=-2.68t^2_{1^{^{^{}}\text{ }}}+301.99t_1+4270.07[/tex]
When
[tex]\begin{gathered} t_1=9\text{ years} \\ P_t=\text{ \$}6770.9 \end{gathered}[/tex]
When
[tex]\begin{gathered} t_1=10 \\ P_t=\text{ \$7021}.97 \end{gathered}[/tex]
Therefore, we can say that in approximately 10 years from 2000.
This means that in the year 2010, we would expect textbook sales to first reach $7 billion