We are given the following information:
The probability that event B occurs is:
[tex]P(B)=\frac{3}{5}[/tex]And the probability that event A occurs given that event B occurs is:
[tex]P(A|B)=\frac{5}{6}[/tex]And we need to find the probability that both A and B occur.
To solve this problem, we have to use the conditional probability formula:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]Where
P(A|B) is the probability of A given that B occurred.
P(B) is the probability of B.
And P(A∩B) is the probability of A and B occuring.
Thus, we solve for P(A∩B) in the previous equation:
[tex]P(A\cap B)=P(A|B)\cdot P(B)[/tex]And substitute the known values:
[tex]P(A\cap B)=\frac{5}{6}\cdot\frac{3}{5}[/tex]We multiply the fractions and get the following result:
[tex]\begin{gathered} P(A\cap B)=\frac{5\cdot3}{6\cdot5} \\ P(A\cap B)=\frac{15}{30} \end{gathered}[/tex]Finally, we simplify the fraction by dividing both numbers in the fraction by 15:
[tex]P(A\cap B)=\frac{1}{2}[/tex]Answer: 1/2