Question

evaluating linear functionsfor f(x) = 1/3x - 2, determine:a, f(9)b, f(-1)c,f(0)

Answer 1

Given the function:

$\text{ f(x) = }\frac{1}{3}\text{x - 2}$

Let's evaluate,

a.) f(9) : It means that we will substitute all x in the equation by 9.

We get,

$\text{ f(x) = }\frac{1}{3}\text{x - 2}$$\text{ f(9) = }\frac{1}{3}(9)\text{ - 2}$$\text{ = }\frac{9}{3}\text{ - 2}$$\text{ = 3 - 2}$$\text{ f(9) = 1}$

Therefore, f(9) = 1.

b.) f(-1) : It means that we will substitute all x in the equation by -1.

We get,

$\text{ f(x) = }\frac{1}{3}\text{x - 2}$$\text{ f(-1) = }\frac{1}{3}(-1)\text{ - 2}$$\text{ = -}\frac{1}{3}-2$$\text{ = -}\frac{1}{3}\text{ - }\frac{6}{3}\text{ = }\frac{-1\text{ - 6}}{3}$$\text{ f(-1) = -}\frac{7}{3}$