Respuesta :

Equation:

[tex]d^2\colon2c-b+3a[/tex]

Replace d with 10, b with 9 , c with 5, and a with 1/3.

[tex]\frac{10^2}{2\cdot5}-9+3\cdot\frac{1}{3}[/tex]

Solve:

[tex]\frac{100}{10}-9+1[/tex][tex]10-9+1[/tex][tex]2[/tex]

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