The general form of a linear equation in the slope-intercept form is:
[tex]\begin{gathered} y=mx+b \\ \text{Where m is the slope and b is the y-intercept value} \end{gathered}[/tex]If the line we are looking for is parallel to y = -2/3 x + 1, so their slopes are the same, so m=-2/3 in the above equation.
And also we know that the line passing through the point (-6, -1), so:
[tex]\begin{gathered} y=-\frac{2}{3}x+b \\ We\text{ evaluate the equation in the point (x,y)=(-6, -1) and find the value of b:} \\ -1=-\frac{2}{3}\cdot(-6)+b \\ -1=2\cdot\frac{6}{3}+b \\ -1=2\cdot2+b \\ -1=4+b\Rightarrow b=-1-4=-5 \end{gathered}[/tex]The equation of the line is:
[tex]y=-\frac{2}{3}x-5[/tex]